JEE Main 2015ChemistryChemical KineticsMediumMCQ

JEE Main 2015 — Chemical Kinetics Question with Solution

JEE Main 2015 (11 Apr Online)

Question

For the equilibrium, Ag⇌Bg, ∆H is -40 kJ/mol . If the ratio of the activation energies of the forward Ef and reverse Eb reactions is 23 then:

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Show full solutionCorrect option: C
Correct answer
CEf=80 kJ/mol, Eb=120 kJ/mol

Step-by-step explanation

 Activation energy is the minimum amount of energy that must be provided for compounds to result in a chemical reaction.

Ag⇌Bg ; ∆H=-40 kJ/mole

∆H=Eaf-Eab=-40 kJ

EafEab=23

⇒ Eaf=23Eab

⇒23 Eab-Eab=-Eab3=-40 kJ

Eab=+120 kJ

Eaf=23×120=80 kJ

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About this question

This is a previous-year question from JEE Main 2015, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.