JEE Main 2026ChemistryClassification of Elements and Periodicity in PropertiesMediumMCQ

JEE Main 2026Classification of Elements and Periodicity in Properties Question with Solution

JEE Main 2026 (24 January Shift 1)

Question

Given below are two statements:
Statement I: is the correct order in terms of metallic character.
Statement II: Atomic radius is always greater than the ionic radius for any element.
In the light of the above statements, choose the correct answer from the options given below

Choose an option

Show full solutionCorrect option: D
Correct answer
DStatement I is true but Statement II is false

Step-by-step explanation

Statement I: Metallic character decreases from left to right across a period and increases down a group. K (Group 1, Period 4) is the most metallic element among these. Mg (Group 2, Period 3) is less metallic than K. Al (Group 13, Period 3) is less metallic than Mg. B (Group 13, Period 2) is a metalloid with the least metallic character. The order K > Mg > Al > B correctly represents decreasing metallic character. TRUE.

Statement II: Atomic radius compared to ionic radius depends on whether the ion is a cation or anion. For metals forming cations: atomic radius > cationic radius (e.g., Na > Na⁺). However, for nonmetals forming anions: atomic radius < anionic radius (e.g., Cl < Cl⁻). The statement claims atomic radius is ALWAYS greater for ANY element, which is incorrect because anions have larger radii than their parent atoms. FALSE.

Correct answer: Statement I is true but Statement II is false.

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About this question

This is a previous-year question from JEE Main 2026, covering the Classification of Elements and Periodicity in Properties chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.