JEE Main 2021 — Coordination Compounds Question with Solution

Hybridization of all the given complexes are given in following table.

$$[Mn(CN{)}_6{]}^{3-}\Rightarrow M{n}^{3+}$$

CN^$$-$$ is a strong field ligand.

$$\therefore$$ Pairing of electron takes place.

$$[Fe(CN{)}_6{]}^{3-}\Rightarrow F{e}^{3+}$$

CN^$$-$$ is a strong ligand.

$$\therefore$$ Pairing of electron takes place.

$$[Co(C_2{O}_4{)}_3{]}^{3-}\Rightarrow C{o}^{3+}$$

$$C_2{O}_4^{2-}$$ acts as strong field ligand with Co³⁺.

$$\therefore$$ Pairing of electrons takes place.

$$[Fe{F}_6{]}^{3-}\Rightarrow F{e}^{3+}$$

F is a weak field ligand.

$$\therefore$$ Pairing of electron does not occurs.

$$[MnC{l}_6{]}^{3-}\Rightarrow M{n}^{3+}$$

Cl^$$-$$ is a weak field ligand.

$$\therefore$$ Pairing of electron does not occurs.

$$[Fe{F}_6{]}^{3-}$$ have 5 unpaired electrons and $$[MnC{l}_6{]}^{3-}$$ have 4 unpaired electrons.

So, both statement I and statement II are true.