JEE Main 2022 — Coordination Compounds Question with Solution

In all complexes, Co is present in $+3$ oxidation state and all complexes are low spin or inner orbital complex.

The stronger the ligand, the higher the crystal field splitting.

So, the order of crystal field splitting is

${\left[\mathrm{Co}(\mathrm{CN}{)}_6\right]}^{3-}>{\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_6\right]}^{3+}>{\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_5\left({\mathrm{H}}_2\mathrm{O}\right)\right]}^{3+}>$ ${\left[\mathrm{CoCl}{\left({\mathrm{NH}}_3\right)}_5\right]}^{2+}$

Shortest wavelength is shown by complex having maximum crystal field splitting.


Spin only magnetic moment $=\sqrt{0(0+2)}=0$ B.M