JEE Main 2004 — Coordination Compounds Question with Solution
From: AIEEE 2004
Question
The correct order of magnetic moments (spin only values in B.M.) among is :
(Atomic numbers: Mn = 25; Fe = 26, Co =27)
(Atomic numbers: Mn = 25; Fe = 26, Co =27)
Choose an option
Show full solutionCorrect option: A
Correct answer
A[MnCl4]2- > [CoCl4]-2 > [Fe(CN)6]-4
Step-by-step explanation
NOTE : The greater the number of unpaired electrons, greater the magnitude of magnetic moment. Hence the correct order will be ${\left[ {MnC{l_4}} \right]^{ - - }} > {\left[ {CoC{l_4}} \right]^{ - - }} > {\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{4 - }}$
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Coordination Compounds chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2004, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.