JEE Main 2014 — Coordination Compounds Question with Solution

(A) [Mg (H₂O)₆ ]²⁺ + (EDTA)^4- $$\frac{\text{buildrel}excessNaOH}{⟶}$$ [Mg (EDTA) ]²⁺ + 6H₂O

The above equation is incorrect because the product formed would be [Mg (EDTA)]²⁻ .

(B) CuSO₄ + KCN $$\to$$ K₂[Cu (CN)₄] + K₂SO₄

The above equation is incorrect. Thus, the correct equation is

2KCN + CuSO₄ $$\to$$ K₂SO₄ + Cu + (CN)₂(Cyanogen Gas)

(C) Li₂O + 2KCl $$\to$$ 2LiCl + K₂O

The above equation is incorrect because K₂O, a stronger base cannot be generated by a weaker base, Li₂O.

(D) [CoCl(NH₃)₅]⁺ + 5H⁺ $$\to$$ Co²⁺ + $$5N{H}_4^{+}$$ + Cl^-

The above equation is correct because amine complexes decomposes under acidic medium. Thus, the complex [CoCl(NH₃)₅] decomposes under acidic conditions to give ammonium ions.