JEE Main 2021 — Coordination Compounds Question with Solution
From: JEE Main 2021 (Online) 24th February Evening Shift
Question
The calculated magnetic moments (spin only value) for species , and respectively are :
Choose an option
Show full solutionCorrect option: B
Correct answer
B4.90, 0 and 1.73 BM
Step-by-step explanation
(i) {[FeC{l_4}]^{2 - }}\buildrel {} \over
\longrightarrow F{e^{2 + }}\buildrel {} \over
\longrightarrow [Ar]3{d^6}
Cl is weak field ligand so does not pairing occur
So, magnetic moment
(n = Number of total unpaired e = 4)
(ii)
C2O4 is strong field ligand so pairing occur.
All electrons are paired, n = 0
hence, = 0
(iii)
Cl is weak field ligand so does not pairing occur
So, magnetic moment
(n = Number of total unpaired e = 4)
(ii)
C2O4 is strong field ligand so pairing occur.
All electrons are paired, n = 0
hence, = 0
(iii)
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Coordination Compounds chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.