JEE Main 2016 — Coordination Compounds Question with Solution
From: JEE Main 2016 (Online) 9th April Morning Slot
Question
Choose an option
Show full solutionCorrect option: C
< [Mo(H2O)6]2+ and
o of [Ti(H2O)6]3+ > [Ti(H2O)6]2+
Step-by-step explanation
0 of complex [Mo(H2O)6]2+ is greater than that of [Cr(H2O)6]2+. It is due to the fact that Mo2+ belongs to second row transition element while Cr2+ is first row transition element.
Magnitude of crystal field splitting energy (0) depends on the charge on the metal ion. Greater the charge, greater is the crystal field splitting energy. Therefore, [Ti(H2O)6]3+ > [Ti(H2O)6]2+.
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This is a previous-year question from JEE Main 2016, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.