JEE Main 2024 — Coordination Compounds Question with Solution

To match List I with List II correctly, we need to identify the colors associated with each compound.

Let's analyze each compound:

1. $${\mathrm{Fe}}_4{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}_3\cdot \mathrm{x}{\mathrm{H}}_2\mathrm{O}$$ - This is known as Prussian Blue.

2. $${\left[\mathrm{Fe}(\mathrm{CN}{)}_5\mathrm{NOS}\right]}^{4-}$$ - This complex is known to have a violet color.

3. $$[\mathrm{Fe}(\mathrm{SCN}){]}^{2+}$$ - This ion is known for its blood red color.

4. $${\left({\mathrm{NH}}_4\right)}_3{\mathrm{PO}}_4\cdot 12{\mathrm{MoO}}_3$$ - This is commonly known as Ammonium phosphomolybdate, which is yellow.

Matching each item, we get:

	LIST I (Compound)		LIST II (Colour)
A.	$${\mathrm{Fe}}_4{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}_3\cdot \mathrm{x}{\mathrm{H}}_2\mathrm{O}$$	III.	Prussian Blue
B.	$${\left[\mathrm{Fe}(\mathrm{CN}{)}_5\mathrm{NOS}\right]}^{4-}$$	I.	Violet
C.	$$[\mathrm{Fe}(\mathrm{SCN}){]}^{2+}$$	II.	Blood Red
D.	$${\left({\mathrm{NH}}_4\right)}_3{\mathrm{PO}}_4\cdot 12{\mathrm{MoO}}_3$$	IV.	Yellow

Based on the analysis, the correct matching is:

Option D: A-III, B-I, C-II, D-IV