JEE Main 2020 — Coordination Compounds Question with Solution
From: JEE Main 2020 (Online) 5th September Morning Slot
Question
The values of the crystal field stabilization
energies for a high spin d6 metal ion in
octahedral and tetrahedral fields, respectively,
are :
Choose an option
Show full solutionCorrect option: C
Correct answer
C–0.40
and –0.6t
Step-by-step explanation
In octahedral
CFSE = [-0.4nt2g + 0.6neg]0
= [-0.44 + 0.62]0
= -0.4 0
In tetrahedral fields
CFSE = [-0.6neg + 0.4nt2g]t
= (– 0.6 × 3 + 0.4 × 3)t
= (–1.8 + 1.2)t
= –0.6t
CFSE = [-0.4nt2g + 0.6neg]0
= [-0.44 + 0.62]0
= -0.4 0
In tetrahedral fields
CFSE = [-0.6neg + 0.4nt2g]t
= (– 0.6 × 3 + 0.4 × 3)t
= (–1.8 + 1.2)t
= –0.6t
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