JEE Main 2020 — Hydrocarbons Question with Solution
From: JEE Main 2020 (Online) 5th September Morning Slot
Question
The minimum number of moles of O2
required for complete combustion of 1 mole of propane and 2
moles of butane is _____.
Enter your answer
Show full solutionCorrect answer: 18
Correct answer
18
Step-by-step explanation
C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(l)
C4H10(g) + O2(g) 4CO2(g) + 5H2O(l)
No. of moles of O2 required to oxidise 1 mole of propane = 5
No. of moles of O2 required to oxidise 1 mole of butane =
So, No. of moles of O2 required to oxidise 1 mole of
propane and 2 moles of butane = 5 + 2 = 18
C4H10(g) + O2(g) 4CO2(g) + 5H2O(l)
No. of moles of O2 required to oxidise 1 mole of propane = 5
No. of moles of O2 required to oxidise 1 mole of butane =
So, No. of moles of O2 required to oxidise 1 mole of
propane and 2 moles of butane = 5 + 2 = 18
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This is a previous-year question from JEE Main 2020, covering the Hydrocarbons chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.