JEE Main 2021ChemistryHydrocarbonsReaction Of AlkenesmediumMCQ

JEE Main 2021Hydrocarbons Question with Solution

From: JEE Main 2021 (Online) 24th February Morning Shift

Question

Identify products A and B.

JEE Main 2021 (Online) 24th February Morning Shift Chemistry - Hydrocarbons Question 94 English

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Show full solutionCorrect option: B
Correct answer
BJEE Main 2021 (Online) 24th February Morning Shift Chemistry - Hydrocarbons Question 94 English Option 2

Step-by-step explanation

In first step, KMnO4(dil.) help to break alkene in ketone and aldehyde and in second step, CrO3 is used for selective over oxidation of aldehyde only. CrO3 will form aldehyde to acid in product (B).

JEE Main 2021 (Online) 24th February Morning Shift Chemistry - Hydrocarbons Question 94 English Explanation

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About this question

This is a previous-year question from JEE Main 2021, covering the Hydrocarbons chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.