JEE Main 2019ChemistryHydrogenMediumMCQ

JEE Main 2019 — Hydrogen Question with Solution

JEE Main 2019 (08 Apr Shift 1)

Question

100 mL  of a water sample contains 0.81 g of calcium bicarbonate and 0.73 g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of CaCO3 is:
(molar mass of calcium bicarbonate is 162 gm mol-1 and magnesium bicarbonate is 146 g mol-1)

Choose an option

Show full solutionCorrect option: D
Correct answer
D10,000 ppm

Step-by-step explanation

neqCaCO3=neqCaHCO32+neqMgHCO32
or, W100×2=0.81162×2+0.73146×2
∴W=1.0
∴ Hardness =1.0100×106=10000 ppm

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About this question

This is a previous-year question from JEE Main 2019, covering the Hydrogen chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.