JEE Main 2022ChemistrySolid StateHardNumerical

JEE Main 2022 — Solid State Question with Solution

JEE Main 2022 (28 Jul Shift 1)

Question

An element M crystallises in a body centred cubic unit cell with a cell edge of 300pm. The density of the element is 6.0 g cm-3. The number of atoms present in 180 g of the element is____×1023. (Nearest integer)

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Show full solutionCorrect answer: 22
Correct answer
22

Step-by-step explanation

M is body centred cubic, ∴ Z=2

Let mass of 1 atom of M is A

Edge length =300pm

Density =6 g/cm3

∴ 6 g/cm3=Z×A300×10-103=2×A27×10-24

A=81×10-24 g

Atoms of M=Total massMass of one atom = 18081×10-24 = 22.22×1023≅22×1023

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About this question

This is a previous-year question from JEE Main 2022, covering the Solid State chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.