JEE Main 2014ChemistrySolid StateMediumMCQ

JEE Main 2014Solid State Question with Solution

JEE Main 2014 (09 Apr Online)

Question

In a face centered cubic lattice atoms A are at the corner points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is :

Choose an option

Show full solutionCorrect option: D
Correct answer
DA2B5

Step-by-step explanation

A atoms at corners  = 8 × 1 8 =  A (one atom)

B atom is missing at One face centre then will present at 5 faces

At face centre atom contribute 1/2 part

Number of B atom at Face centre = 5× 1 2 (B atom)

So formula of compound = A2B5

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Solid State chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2014, covering the Solid State chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.