JEE Main 2024ChemistrySolutionsMediumNumerical

JEE Main 2024 — Solutions Question with Solution

JEE Main 2024 (29 Jan Shift 2)

Question

Molality of 0.8M H2SO4 solution (density 1.06 g cm-3 ) is _______×10-3 m.

Round off your answer to the nearest integer.

Enter your answer

Show full solutionCorrect answer: 815
Correct answer
815

Step-by-step explanation

1000 ml solution contains 0.8 mol of H2SO4

Mass of solution = 100cm3×1.06 gcm3= 1060 g

Mass of solute (H2SO4) =0.8 × 98 =78.4g

Mass of solvent = 1060 -78.4 =981.6 g

Molality = moles of H2SO4mass of solvent (in kg)

=0.8981.6×10−3 = 0.815m

= 815×10-3 m

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Solutions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2024, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.