JEE Main 2019ChemistrySolutionsMediumMCQ

JEE Main 2019 — Solutions Question with Solution

JEE Main 2019 (09 Apr Shift 1)

Question

The osmotic pressure of a dilute solution of an ionic compound XY in water is four times that of a solution 0.01 M BaCl2 in water. Assuming complete dissociation of the given ionic compounds in water, the concentration of XY ( in mol L-1 ) in solution is

Choose an option

Show full solutionCorrect option: D
Correct answer
D6×10-2

Step-by-step explanation

Osmotic pressure π=i×CRT

i=Van't hoff factor

According to question,

for XY i=2, BaCl2 i=3

πXY=4×πBaCl2

2×C×RT=4×3×0.01×RT

C=6×0.01=0.06 M

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About this question

This is a previous-year question from JEE Main 2019, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.