JEE Main 2020ChemistrySolutionsMediumNumerical

JEE Main 2020Solutions Question with Solution

JEE Main 2020 (06 Sep Shift 1)

Question

The elevation of boiling point of 0.10m aqueous CrCl3.xNH3 solution is two times that of 0.05 m aqueous CaCl2 solution. The value of x is ..
[Assume 100% ionisation of the complex and CaCl2, coordination number of Cr as 6, and that all NH3 molecules are present inside the coordination sphere]

Enter your answer

Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

0.05m aqueous CaCl2 =0.15molal solution of non electrolyte

Since the elevation in boiling point is double so the molality of given solution of complex =0.3m

Hence the complex must be producing three ions in the solution, so its formula =CrNH35ClCl2

SO X=5

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Solutions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.