JEE Main 2021ChemistrySolutionsEasyNumerical

JEE Main 2021 — Solutions Question with Solution

JEE Main 2021 (25 Jul Shift 2)

Question

When 3.00 g of a substance X' is dissolved in 100 g of CCl4, it raises the boiling point by 0.60 K. The molar mass of the substance ' X' is  ___ g mol-1.
(Nearest integer).
[Given Kb for CCl4 is 5.0 K kg mol-1

Enter your answer

Show full solutionCorrect answer: 250
Correct answer
250

Step-by-step explanation

ΔTb=Kb× molality

0.60=5×3/M100/100

M=Molar mass

M=250.

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About this question

This is a previous-year question from JEE Main 2021, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.