JEE Main 2022ChemistrySome Basic Concepts of ChemistryEasyMCQ

JEE Main 2022 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2022 (29 Jul Shift 2)

Question

Consider the reaction

4HNO3l+3KCls→Cl2g+NOClg+2H2Og+3KNO3s

The amount of HNO3 required to produce110.0 g of KNO3 is

(Given : Atomic masses of H,O,N and K are 1,16,14 and 39, respectively.)

Choose an option

Show full solutionCorrect option: C
Correct answer
C91.5 g

Step-by-step explanation

4HNO3l+3KCls→Cl2g+NOClg+2H2Og+3KNO3g

                        HNO3                          KNO3Weight            Xgm                             110gmmoles                 x63                              110101

As per the stoichiometric equation4 moles of HNO3→3 moles of KNO3

1→34

x63→34×x63=110101

x=110×63×4101×3=91.5gm

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About this question

This is a previous-year question from JEE Main 2022, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.