JEE Main 2018ChemistrySome Basic Concepts of ChemistryMediumMCQ

JEE Main 2018 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2018 (15 Apr)

Question

A sample of NaClO3 is converted by heat to NaCl with a loss of 0.16 g of oxygen. The residue is dissolved in water and precipitated as AgCl. The mass of AgCl (in g) obtained will be: (Given: Molar mass of AgCl=143.5 g mol-1)

Choose an option

Show full solutionCorrect option: D
Correct answer
D0.48

Step-by-step explanation

2NaClO3→∆2NaCl+3O2
2 moles of NaCl=3 moles of oxygen
nNaCl=0.1632×23=1200×23=1300
The number of moles of NaCl=The number of moles of AgCl
1300=nAgCl
Weight of AgCl=1300×108+35.5=1300×143.5
=0.48 g

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About this question

This is a previous-year question from JEE Main 2018, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.