JEE Main 2021ChemistrySome Basic Concepts of ChemistryEasyNumerical

JEE Main 2021 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2021 (24 Feb Shift 2)

Question

The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O2 for complete oxidation and produces 4 times its own volume of CO2 is CxHy. The value of y is ________.

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Show full solutionCorrect answer: 8
Correct answer
8

Step-by-step explanation

Combustion reaction.

CxHy(g)+x+y4O2g→xCO2g+y2H2Oℓ

V               6 V             --                -                        Vx=4V

⇒x=4

Since: I Vo2=6×VCxHy

⇒Vx+y4=6 V

⇒x+y4=6⇒4+y4=6

⇒y=8

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About this question

This is a previous-year question from JEE Main 2021, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.