JEE Main 2023ChemistrySome Basic Concepts of ChemistryEasyMCQ

JEE Main 2023 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2023 (10 Apr Shift 2)

Question

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: 3.1500 g of hydrated oxalic acid dissolved in water to make 250.0 mL solution will result in 0.1 M oxalic acid solution.

Reason R: Molar mass of hydrated oxalic acid is 126 g mol–1 .

In the light of the above statements, choose the correct answer from the options given below: 

 

Choose an option

Show full solutionCorrect option: C
Correct answer
CBoth A and R are true and R is the correct explanation of A

Step-by-step explanation

Molarity (M) = wtmwt × V × 1000

Using this formula, we can calculate the molarity of the oxalic acid solution as follows:

  1. Mass of hydrated oxalic acid = 3.1500 g
  2. Molar mass of hydrated oxalic acid(H2C2O4·2H2O) = 126.064 g/mol
  3. Volume of the solution = 250.0 mL

Molarity (M)=3.15×1000126×250=0.10

So both assertion land reason are correct.

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About this question

This is a previous-year question from JEE Main 2023, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.