JEE Main 2021ChemistrySome Basic Concepts of ChemistryMediumNumerical

JEE Main 2021 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2021 (27 Aug Shift 2)

Question

100 g of propane is completely reacted with 1000 g of oxygen. The mole fraction of carbon dioxide in the resulting mixture is x×10-2. The value of x is (Nearest integer)

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Show full solutionCorrect answer: 19
Correct answer
19

Step-by-step explanation

          C3H8(g) +  5O2(g)⟶3CO2( g)+4H2O(ℓ)

t=02.27 mole 31.25 mol

t=∞0      19.9 mol       6.81 mol   9.08 mol

mole fraction of CO2 in the final reaction mixture (heterogeneous)

XCO2=6.8119.9+6.81+9.08

=0.1902=19.02×10-2⇒19

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About this question

This is a previous-year question from JEE Main 2021, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.