JEE Main 2021ChemistrySome Basic Concepts of ChemistryEasyNumerical

JEE Main 2021 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2021 (26 Aug Shift 2)

Question

100 mL of Na3PO4 solution contains 3.45 g of sodium. The molarity of the solution is .....×10-2 mol L-1. (Nearest integer)
[Atomic Masses - Na:23.0u,O:16.0u,P:31.0u]

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Show full solutionCorrect answer: 50
Correct answer
50

Step-by-step explanation

Number of mole of Na+ ion =3.4523 mol

So number of mole of Na3PO4=3.453×23=0.050 mol

Molarity =0.050100×1000=0.50=50×10-2M

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About this question

This is a previous-year question from JEE Main 2021, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.