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JEE Main 2016 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2016 (09 Apr Online)

Question

The amount of arsenic pentasulphide that can be obtained when 35.5 g arsenic acid is treated with excess H2S in the presence of conc. HCl (assuming 100% conversion) is

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Show full solutionCorrect option: D
Correct answer
D0.125 mol

Step-by-step explanation

2H3AsO4+5H2S→Conc.HClAs2S5+8H2O

2 moles of Arsenic Acid → 1 mole of Arsenic Pentasulphide

1 moles of Arsenic Acid → 1/2 mole of Arsenic Pentasulphide

Molar mass of H3AsO4=141; Molar mass of As2S5=308

∴ Number of moles of H3AsO4=35.5141=0.25

∴  Number of moles of As2S5=0.252=0.125 mol

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About this question

This is a previous-year question from JEE Main 2016, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.