JEE Main 2013ChemistrySome Basic Concepts of ChemistryHardMCQ

JEE Main 2013 — Some Basic Concepts of Chemistry Question with Solution

JEE Main 2013 (07 Apr)

Question

A gaseous hydrocarbon on combustion gives 0.72 g of water and 3.08 g CO2. What is the empirical formula of the hydrocarbon?

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Show full solutionCorrect option: B
Correct answer
BC7H8

Step-by-step explanation

C x H y + x + y 4 O 2 ⟶ xC O 2 + y 2 H 2 O

Moles of CO2 = 3 . 0 8 4 4 = 0 . 0 7  moles = x

Moles of H2O = 0 . 7 2 1 8 = 0 . 0 4  moles = y 2

x = 0.07 g atoms of carbon

y = 0.08 g atoms of hydrogen

   x       :        y0.07        0.08   7              8

Empirical formula becomes C7H8.

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About this question

This is a previous-year question from JEE Main 2013, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.