JEE Main 2023 — Surface Chemistry Question with Solution

The coagulating power of an electrolyte is inversely proportional to its coagulating value. That is,

$$\text{Coagulating power}=\frac{1}{\text{Coagulating value}}$$

Therefore, the coagulating power of AlCl₃ is $$\frac{1}{0.09}$$

and the coagulating power of NaCl is $$\frac{1}{50.04}$$

We are asked to find the factor by which the coagulating power of AlCl₃ is greater than the coagulating power of NaCl. This factor is given by the ratio

$$x=\frac{\text{Coagulating power of AlCl₃}}{\text{Coagulating power of NaCl}}=\frac{\frac{1}{0.09}}{\frac{1}{50.04}}=\frac{50.04}{0.09}$$

$$x=\frac{50.04}{0.09}\approx 556.22$$

So, the coagulating power of AlCl₃ is approximately 556 times the coagulating power of NaCl.

However, since the problem asks for the nearest integer, the answer would be 556.