JEE Main 2019 — Surface Chemistry Question with Solution
From: JEE Main 2019 (Online) 9th January Morning Slot
Question
Adsorption of a gas follows Freundlich adsorption isotherm. In the given plot, x is the mass of the gas adsorbed on mass m of the adsorbent at pressure P. is proportional to :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: C
Correct answer
CP
Step-by-step explanation
According to Freundlich adsorption isotherm, in the median range of pressure
= kP
taking log both sides, we get,
log = logk + logP
Here in graph between log and logP, slope is and intercepts = log k.
From the given graph,
slope = =
=
n = 2
= kP
= kP
taking log both sides, we get,
log = logk + logP
Here in graph between log and logP, slope is and intercepts = log k.
From the given graph,
slope = =
=
n = 2
= kP
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This is a previous-year question from JEE Main 2019, covering the Surface Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.