JEE Main 2020 — Surface Chemistry Question with Solution
From: JEE Main 2020 (Online) 8th January Morning Slot
Question
As per Hardy-Schulze formulation, the flocculation values of the following for ferric hydroxide sol are in the
order :
Choose an option
Show full solutionCorrect option: B
Correct answer
BK3[Fe(CN)6] < K2CrO4 < KBr = KNO3 = AlCl3
Step-by-step explanation
Since, Fe(OH)3 is positively charged sol, hence,
anionic charge will flocculate.
As per Hardy Schulze rules coagulation power of anion follows the order :
Fe(CN)63– CrO42– Cl– = Br– = NO3–
Higher the coagulation power lower will be its flocculation value therefore order will be :
Fe(CN)63– CrO42– Cl– = Br– = NO3–
As per Hardy Schulze rules coagulation power of anion follows the order :
Fe(CN)63– CrO42– Cl– = Br– = NO3–
Higher the coagulation power lower will be its flocculation value therefore order will be :
Fe(CN)63– CrO42– Cl– = Br– = NO3–
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