16 JEE Main 2026 Area Under Curves previous-year questions with verified answers and step-by-step solutions.
These are the JEE Main 2026 previous-year questions from the Area Under Curves chapter of Mathematics. Each links to a full solution with a verified answer key. To see the whole chapter across all years, visit the Area Under Curves chapter hub.
The area of the region \(x, y) : x² - 8x ≤ y ≤ -x\ is :
The area of the region \(x, y) : 0 ≤ y ≤ 6 - x, y² ≥ 4x - 3, x ≥ 0\ is:
The area of the region \(x, y): y ≤ π - |x|, y ≤ |x x|, y ≥ 0\ is:
Let the area of the region bounded by the curve y= x, x\, lines x=0, x=(3 π)/(2), and the x-axis be A. Then, A+A² is eq…
The area of the region enclosed between the circles x²+y²=4 and x²+(y-2)²=4 is:
If the area of the region bounded by 16x² - 9y² = 144 and 8x - 3y = 24 is A, then 3(A + 6 (3)) is equal to _______.
Let f(α) denote the area of the region in the first quadrant bounded by x=0, x=1, y²=x and y=|α x-5|-|1-α x|+α x². Then…
If the area of the region \(x, y): 1-2 x y 4-x², x 0, y 0 \ is (α)/(β), α, β N, gcd(α, β)=1, then the value of (α+β) is…
The area of the region R = \(x, y): xy ≤ 27, 1 ≤ y ≤ x²\ is equal to:
Let the line x=-1 divide the area of the region \(x, y): 1+x² ≤ y ≤ 3-x \ in the ratio m: n, gcd(m, n)=1. Then m+n is e…
Log in to unlock the full list, track what you've solved, and practice on the TCS iON-style CBT player. It's free.