JEE Main 2020MathematicsLimitsEasyMCQ

JEE Main 2020Limits Question with Solution

JEE Main 2020 (02 Sep Shift 2)

Question

limx0tanπ4+x1/x is equal to

Choose an option

Show full solutionCorrect option: D
Correct answer
De2

Step-by-step explanation

limx0tanπ4+x1/x         1form

=elimx0tanπ4+x-1x             limxafxgx=elimxagxfx-1, limxafx=1 & limxagx=

=elimx01+tanx1-tanx-1x

=elimx02tanxx1-tanx 

=elimx0tanxx21-tanx

 =e121-0=e2

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About this question

This is a previous-year question from JEE Main 2020, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.