JEE Main 2015MathematicsLimitsMediumMCQ

JEE Main 2015 — Limits Question with Solution

JEE Main 2015 (04 Apr)

Question

limx→01-cos2x3+cosxxtan4x=

Choose an option

Show full solutionCorrect option: D
Correct answer
D2

Step-by-step explanation

limx→0⁡(1-cos⁡2x)  (3+cos⁡x)xtan⁡4x

= limx→0⁡2sin2⁡x ⋅(3+cos⁡x)x⋅tan⁡4x

= limx→0⁡2⋅sin⁡xx2⋅3+cosxtan⁡4x4x ⋅4

= 2⋅12 ⋅(3+1)1 ⋅4

=2 .

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About this question

This is a previous-year question from JEE Main 2015, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.