JEE Main 2022MathematicsLimitsEasyMCQ

JEE Main 2022 — Limits Question with Solution

JEE Main 2022 (29 Jun Shift 2)

Question

The value of limx→1x2-1sin2πxx4-2x3+2x-1 is equal to:

Choose an option

Show full solutionCorrect option: D
Correct answer
Dπ2

Step-by-step explanation

Given, limx→1x2-1sin2πxx4-2x3+2x-1

=limx→1x2-1sin2πxx2-1x2-2x+1

=limh→0sin2π1+h1+h-12

=limh→0sin2πhh2=limh→0sinπhπh2π2=π2

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About this question

This is a previous-year question from JEE Main 2022, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.