JEE Main 2016MathematicsLimitsMediumMCQ

JEE Main 2016 — Limits Question with Solution

JEE Main 2016 (10 Apr Online)

Question

limx→0⁡1-cos⁡2x22xtan⁡x-xtan⁡2x is

Choose an option

Show full solutionCorrect option: C
Correct answer
C-2

Step-by-step explanation

limx→0⁡1-cos⁡2x22xtan⁡x-xtan⁡2x

= limx→0⁡2sin2⁡x22xx+x33+2x515+…-x2x+23 x33+225 x515+…

= limx→0⁡4x-x33!+x55!-….4x423-83+x6415-6415

(dividing numerator and denominator by x4 )

= limx→0⁡41-x23!+x45!-….4-2+x2-6015+…

= -2

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About this question

This is a previous-year question from JEE Main 2016, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.