JEE Main 2018MathematicsLimitsHardMCQ

JEE Main 2018 — Limits Question with Solution

JEE Main 2018 (08 Apr)

Question

For each t∈R, let t be the greatest integer less than or equal to t. Thenlimx→0+x1x+2x+…+15x

Choose an option

Show full solutionCorrect option: D
Correct answer
Dis equal to 120

Step-by-step explanation

We know that

1x−1<1x≤1x

Hence, 

1+2+3. . .+15x−15<1x+2x+....+15x≤1+2+...+15x

⇒limx→0+x1x+2x+....+15x=15162

=120

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About this question

This is a previous-year question from JEE Main 2018, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.