JEE Main 2017MathematicsLimitsMediumMCQ

JEE Main 2017Limits Question with Solution

JEE Main 2017 (02 Apr)

Question

limxπ2cotx-cosxπ-2x3 equals

Choose an option

Show full solutionCorrect option: B
Correct answer
B116

Step-by-step explanation

Put, x=π2-h in the given limit, we get

=limh0cotπ2-h-cosπ2-hπ-2×π2-h3

=limh0tanh-sinhπ-2×π2+2h3

=limh0tanh-sinh8h3

= 18 limh0sinhhsech-1h2

=18 limh0sinhhlimh01-coshcosh h2

=18 ×1×limh01-coshcosh h2

=18 limh02sin2h2cosh h2

=18 limh02sin2h2h24×4×cosh

=116.

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About this question

This is a previous-year question from JEE Main 2017, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.