JEE Main 2018MathematicsLimitsMediumMCQ

JEE Main 2018 — Limits Question with Solution

JEE Main 2018 (16 Apr Online)

Question

limx→0(27+x)13-39-(27+x)23 equals 

Choose an option

Show full solutionCorrect option: A
Correct answer
A-16

Step-by-step explanation

Given limit is limx→027+x13-3 9-27+x23   00 form

Applying L'Hospital's rule,

⇒limx→0 1327+x-23 -2327+x-13=27-23-227-13

=-122713 =-16.

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About this question

This is a previous-year question from JEE Main 2018, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.