JEE Main 2020MathematicsLimitsEasyMCQ

JEE Main 2020 — Limits Question with Solution

JEE Main 2020 (08 Jan Shift 1)

Question

limx→03x2+27x2+21x2 is equal to

Choose an option

Show full solutionCorrect option: B
Correct answer
B1e2

Step-by-step explanation

Let L=limx→03x2+27x2+21x2

=elimx→01x23x2+27x2+2-1

=elimx→0-4x27x2+2

=e-42

=e-2

=1e2

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About this question

This is a previous-year question from JEE Main 2020, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.