JEE Main 2021MathematicsQuadratic EquationEasyMCQ

JEE Main 2021 — Quadratic Equation Question with Solution

JEE Main 2021 (27 Jul Shift 1)

Question

Let α,β be two roots of the equation x2+201/4x+51/2=0. Then α8+β8 is equal to

Choose an option

Show full solutionCorrect option: C
Correct answer
C50

Step-by-step explanation

Given, 

x2+201/4x+51/2=0

⇒x2+5=-x2014

⇒x2+52=20x2

⇒x4+5+2×x2×5=20x2

⇒x4=-5⇒x8=25

So, α8+β8=25+25=50

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About this question

This is a previous-year question from JEE Main 2021, covering the Quadratic Equation chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.