JEE Main 2021MathematicsQuadratic EquationMediumMCQ

JEE Main 2021 — Quadratic Equation Question with Solution

JEE Main 2021 (24 Feb Shift 1)

Question

Let p and q be two positive numbers such that p+q=2 and p4+q4=272. Then p and q are roots of the equation:

Choose an option

Show full solutionCorrect option: D
Correct answer
Dx2-2x+16=0

Step-by-step explanation

Consider p2+q22-2p2q2=272

p+q2-2pq2-2p2q2=272

16-16pq+2p2q2=272

pq2-8pq-128=0

pq2-8pq-128=0

pq=8±242=16,-8

∴  pq=16

∴  Required equation

: x2-2x+16=0

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About this question

This is a previous-year question from JEE Main 2021, covering the Quadratic Equation chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.