JEE Main 2023PhysicsAtomic PhysicsMediumMCQ

JEE Main 2023Atomic Physics Question with Solution

JEE Main 2023 (01 Feb Shift 1)

Question

The mass of proton, neutron and helium nucleus are respectively 1.0073 u, 1.0087 u and 4.0015u. The binding energy of helium nucleus is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B28.4 MeV

Step-by-step explanation

Given here,  mHe=4.0015 ump=1.0073 u and mn=1.0087 u.

Mass defect

 m = 2mp+2mn-mHe=2×1.0073+2×1.0087-4.0015=0.0305 u

Binding energy 

E = m×931 MeV=0.0305×931=28.4 MeV

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Atomic Physics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Atomic Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.