JEE Main 2023PhysicsAtomic PhysicsMediumMCQ

JEE Main 2023Atomic Physics Question with Solution

JEE Main 2023 (06 Apr Shift 1)

Question

The energy levels of an hydrogen atom are shown below. The transition corresponding to emission of shortest wavelength is

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Show full solutionCorrect option: A
Correct answer
AD

Step-by-step explanation

Wavelength of photons released during de-excitation is given by,

1λ=R1n12-1n22.

Clearly, shortest wavelength will correspond to highest energy difference in de-excitation, which in the given figure will correspond to transition from n=3 to n=1.

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About this question

This is a previous-year question from JEE Main 2023, covering the Atomic Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.