JEE Main 2019PhysicsAtomic PhysicsMediumMCQ

JEE Main 2019Atomic Physics Question with Solution

JEE Main 2019 (12 Apr Shift 2)

Question

The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths λ1λ2 of the photons emitted in this process is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B207

Step-by-step explanation

1λ1=R132-142= R×7144
1λ2=R122-132= R×536
λ1λ2=R×536×144R×7=207

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Atomic Physics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2019, covering the Atomic Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.