JEE Main 2019PhysicsAtomic PhysicsEasyMCQ

JEE Main 2019Atomic Physics Question with Solution

JEE Main 2019 (09 Apr Shift 2)

Question

A He+ ion is in its first excited state. Its ionization energy is:

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Show full solutionCorrect option: A
Correct answer
A13.60 eV

Step-by-step explanation

E=-13.6z2n2
=-13.62222=-13.60 eV
Total energy of He+ ion is in its first excited state is -13.60 eV . Hence, its ionization energy will be 13.60 eV 

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About this question

This is a previous-year question from JEE Main 2019, covering the Atomic Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.