JEE Main 2018PhysicsAtomic PhysicsMediumMCQ

JEE Main 2018 — Atomic Physics Question with Solution

JEE Main 2018 (15 Apr)

Question

The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from helium atom. The total energy required to ionize the Helium atom completely is close to

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Show full solutionCorrect option: C
Correct answer
C79 eV

Step-by-step explanation

The energy is required to remove e − from singly ionized helium atom= 54.4 eV. The energy required to remove e − from a helium atom =x eV, given 54.4 eV=2.2 x⇒x=24.73 eV. The energy required to ionize helium atom = 79.13 eV≈79 eV.

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About this question

This is a previous-year question from JEE Main 2018, covering the Atomic Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.