JEE Main 2022 — Atomic Physics Question with Solution
JEE Main 2022 (27 Jun Shift 2)
Question
Given below are two statements
Statement I: In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit to higher energy orbit , is given as
Statement II: The jumping of electron from higher energy orbit to lower energy orbit is associated with frequency of radiation given as . This condition is Bohr's frequency condition.
In the light of the above statements, choose the correct answer from the options given below:
Choose an option
Show full solutionCorrect option: D
Step-by-step explanation
According to Bohr's model, when electron makes the transition from lower orbit to higher orbit, its energy can be given as
, here, is Planck's constant.
Then, .
Bohr's frequency condition is the law that state that the frequency of the radiation emitted or absorbed during the transition of an atomic system between two stationary states equals the difference in the energies of the states divided by Planck's constant.
Hence, Statement I is incorrect but statement II is true.
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