JEE Main 2023PhysicsCapacitanceEasyMCQ

JEE Main 2023 — Capacitance Question with Solution

JEE Main 2023 (13 Apr Shift 2)

Question

In the network shown below, the charge accumulated in the capacitor in steady state will be:

 

Choose an option

Show full solutionCorrect option: D
Correct answer
D7.2μC

Step-by-step explanation

In steady state, capacitor behaves as open circuit, so no current will flow.

The total resistance of the circuit is, R=6+4 Ω=10 Ω

The current flowing through the circuit is

I=3 V10 Ω

Potential difference on 6 Ω resistor

V'=310×6=1.8 V

The charge on the capacitor is,

Q=CV'=4 μF×1.8 V=7.2 μC

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About this question

This is a previous-year question from JEE Main 2023, covering the Capacitance chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.