JEE Main 2024PhysicsCapacitanceEasyNumerical

JEE Main 2024Capacitance Question with Solution

JEE Main 2024 (30 Jan Shift 1)

Question

A capacitor of capacitance C and potential V has energy E. It is connected to another capacitor of capacitance 2C and potential 2V. Then the loss of energy is x3E, where x is _______.

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Show full solutionCorrect answer: 2
Correct answer
2

Step-by-step explanation

Given, E=12CV2

Required energy loss 

=12C1C2C1+C2V1-V22=12C×2CC+2CV-2V2

=26CV2=23·E

x=2

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About this question

This is a previous-year question from JEE Main 2024, covering the Capacitance chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.