JEE Main 2022PhysicsCapacitanceEasyMCQ

JEE Main 2022 — Capacitance Question with Solution

JEE Main 2022 (26 Jun Shift 2)

Question

A parallel plate capacitor with plate area A and plate separation d=2 m has a capacitance of 4 μF. The new capacitance of the system if half of the space between them is filled with a dielectric material of dielectric constant K=3 (as shown in figure) will be

Choose an option

Show full solutionCorrect option: C
Correct answer
C6 μF

Step-by-step explanation

This parallel plate capacitor can be divided into two capacitors. One with dielectric C1 and other without dielectricC2. The two capacitors will be in series.

Initially C=ε0Ad=4 μF

Now, C1=kε0Ad2=2×3×ε0Ad=24 μF and C2=ε0Ad2=2×ε0Ad=8 μF

Finally C'=C1C2C1+C2=24×824+8=6 μF

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Capacitance chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Capacitance chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.